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2m^2+27m-14=0
a = 2; b = 27; c = -14;
Δ = b2-4ac
Δ = 272-4·2·(-14)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-29}{2*2}=\frac{-56}{4} =-14 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+29}{2*2}=\frac{2}{4} =1/2 $
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